线性代数提高矩阵运算linear-algebra-1:线性代数:14:第十四章相似矩阵:基础题:三-解答题:4:169线性代数做题本（一）解答版解答题不看本题本题讨论已掌握查看解析收入错题#8552设 A=(1−11x4y−3−35),A∼ΛA = \left(\begin{array}{rrr} 1 & - 1 & 1 \\ x & 4 & y \\ - 3 & - 3 & 5 \end{array}\right),A \sim \LambdaA=1x−3−14−31y5,A∼Λ,且 λ=2\lambda = 2λ=2 是 AAA 的二重特征值,求 x,yx,yx,y 的值及可逆矩阵 PPP,使得 P−1AP =Λ{P}^{-1}{AP} \; = \LambdaP−1AP=Λ.