高等数学提高中值定理证明题查看解析已掌握收入错题本题讨论不看本题#9347设可导函数 f(x)f\left(x\right)f(x) 严格单调递增且满足 ∫−11f(x)dx=0{\int }_{-1}^{1}f\left(x\right) \mathrm{d}x = 0∫−11f(x)dx=0,记 a=∫01f(x)dxa = {\int }_{0}^{1}f\left(x\right) \mathrm{d}xa=∫01f(x)dx.(1) 证明 a>0a > 0a>0;(2) 令 F(x)=a(1−x2)+∫1xf(t)dtF\left(x\right) = a\left({1 - {x}^{2}}\right) + {\int }_{1}^{x}f\left(t\right) {dt}F(x)=a(1−x2)+∫1xf(t)dt,证明:存在 ξ∈(−1,1)\xi \in \left({-1,1}\right)ξ∈(−1,1),使得 F′′(ξ)=0{F}^{\prime \prime }\left(\xi \right) = 0F′′(ξ)=0.